3q^2+q-90=0

Solution for 3q^2+q-90=0 equation:

3q^2+q-90=0

a = 3; b = 1; c = -90;
Δ = b2-4ac
Δ = 12-4·3·(-90)
Δ = 1081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1081}}{2*3}=\frac{-1-\sqrt{1081}}{6}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1081}}{2*3}=\frac{-1+\sqrt{1081}}{6}
$